A projectile is launched horizontally from a height of 2.2 meters at 32 m/s. How far will it travel horizontally before it hits the ground?

Total distance covered horizontally S= 21.44 m

Explanation:

Given: Height h=2.2 m, Speed Vx=32 m/s

Required: Total distance covered horizontally S=?

Sol. we have

Distance = Speed (horizontal component)× Time

so we fist calculate time to the ground. so using data

Initial Velocity Vyi = 0 m/s  (Zero Vertical component as launched horizontally).

g = 9.81 m/s²

using equation h = Vyi t + 1/2 (at²)

⇒ 2.2 m = 0 m/s ×t + 4.905 m/s²  ×  t²

t² = 2.2 m / 4.905 m/s² = 0.4485219164118247 s²

t = 0.67 s

Total distance covered horizontally S= 32 m/s × 0.67 s = 21.44 m