A student wishes to determine the heat capacity of a coffee-cup calorimeter. After she mixes 108.7 g of water at 60.2°C with 108.7 g of water, already in the calorimeter, at 19.3°C, the final temperature of the water is 35.0°C. Calculate the heat capacity of the calorimeter in J/K. Use 4.184 J/g°C as the specific heat of water. Enter to 1 decimal place.

Answer : The heat capacity of the calorimeter is,

Explanation :

In this problem we assumed that heat given by the hot body is equal to the heat taken by the cold body.

where,

= specific heat of water =

= specific heat of calorimeter = ?

= mass of water = 108.7 g

= mass of calorimeter = 108.7 g

= final temperature of mixture =

= initial temperature of water =

= initial temperature of calorimeter =

Now put all the given values in the above formula, we get

Therefore, the heat capacity of the calorimeter is,

probably not the "magnets"in the magnet, so to speak, are thought to be electrons orbiting in shells. vurrent loops two sides to the loop

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