Physics, 19.02.2020 03:47 sasalove

A three-phase balanced wye-wye system has a line voltage of 208Vୖ୑ୗ. The line current is 6Aୖ୑ୗ and the total real power absorbed by the load is 1800W. Determine the load impedance per phase if the line impedance is negligible. Assume the load is inductive.

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Answer from: alexanderturnerat

16.67 + j11.08 Ω

Explanation:

To determine the load impedance per phase if the line impedance, we need to find the Line to Line voltage of a balanced system and the real power absorbed by the load. So lets take it one after the other.

The formula for Line to Line Voltage for this balanced system can be represented as:

| $V_{an$ | = $\frac{|V_{ab}|}{\sqrt{3} }$

where | $V_{ab}$ | = 208 V rms

∴ | $V_{an$ | = $\frac{208}{\sqrt{3} }$

| $V_{an$ | = 120.09 V rms

Now, to the real power absorbed by the load

P = 3 ( $V_{an}$ )( $I_{aA$ ) cos θ

where:

P = 1800 W

$V_{an}$ = 120.09 V rms

$I_{aA$ = 6 A

cos θ =???

substituting our known data to determine our unknown data; we have:

1800 = 3(120.09 × 6 × cos θ)

cos θ = $\frac{1800}{3(120.09*6)}$

cos θ = $\frac{1800}{2161.62}$

cos θ = 0.8327

θ = cos⁻¹ (0.8327)

θ = 33.62°

angle θ depicts the value of the real power factor

To determine the load impedance per phase; we have:

$Z_{load}=\frac{V_{an}}{I_{aA}}< \theta$

$Z_{load}=\frac{120.09}{6}$

$Z_{load}=20.02$

$Z_{load}=$ 16.67 + j11.08 Ω

Hence, the load impedance per phase if the line impedance is negligible = 16.67 + j11.08 Ω

Answer from: Quest

scattering of light by tiny particles in air to produce the colors we see on sky, is dependent on the following factors:

(i) wavelength of light

(ii) size of the scattering particle

(iii) distance traveled by light through the atmosphere.

according to rayleigh's law of scattering, the amount of scattering is inversely proportional to the fourth power of its wavelength. shorter the wavelength, greater is its scattering. hence violet/blue light is scattered more than red.

sun's light is a composite light ( visible light) with wavelengths in the range 400 nm (violet) to 700 nm (red). as sunlight passes through our atmosphere, the molecules of air scatter light according to their wavelengths. during sunrise and sunset, the sun's position is below the horizon. hence light from the sun travels a greater distance in the atmosphere when compared to its position a noon.

as sunlight enters the earth's atmosphere, blue light is scattered away and at the end of its journey in the sky, only red and orange wavelengths remain in the beam.

hence at sunrise and sunset, the sky appears reddish orange.

Answer from: Quest

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A three-phase balanced wye-wye system has a line voltage of 208Vୖ୑ୗ. The line current is 6Aୖ୑ୗ and t...

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