The plates of a parallel plate capacitor are separated by d = 1.6 cm. The potential of the negative plate is 0 V, and the potential halfway between the plates is +15 V (see the drawing). What is the electric field between the plates (take the upward direction as the positive direction)? Be sure to include the proper + or - sign.

The electric field between the plates is 1875 V/m.

Explanation:

Given that,

Separated d=1.6 cm

Potential of negative plate = 0 V

Potential halfway between the plates = 15 V

We need to calculate the total potential

Using formula of potential

Put the value into the formula

We need to calculate the electric field between the plates

Using formula of electric field

Direction is negative as the field always points from positive  to negative plate

Hence, The electric field between the plates is 1875 V/m.

here we know that ball will drop down by total distance 3.2 m

so here we know that

now using kinematics

now in the same time it will cover horizontal distance of 0.75 m

so speed of the ball will be