An object slides down a rough inclined plane with some non-zero acceleration a1. (There is friction).The same mass is shoved up the same incline with a large, brief initial push. As the mass moves up the incline, its acceleration is a2. What can be said about the acceleration of the box?

W= fd
where f is an applied force and d is the distance over which it is applied. when a parachuting skydiver is at constant velocity, he is experiencing "terminal velocity", the point at which his acceleration down is canceled out by air resistance. that means that the resisting force of the air is equal to his weight, but in the opposite direction. with this, we can solve for the work done by the force.
w = fd
w = (92.0)(9.81 m/s^2) (325)
w= 2.93 x 10^5 j
the value for work in this case is positive because it is pushing up on the skydiver, who has a downward force of gravity.
therefore the answer is 2.93 x 10^5 j

To a fellow spongebob-ian i will be glad to , the cheetah didn't get far on purpose because he's a cheetah  ( ͡° ͜ʖ ͡°)