A car of mass 1000.0 kg is traveling along a level road at 100.0 km/h when its brakes are applied. Calculate the stopping distance if the coefficient of kinetic friction of the tires is 0.500. Neglect air resistance. (Hint: since the distance traveled is of interest rather than the time, xx is the desired independent variable and not tt. Use the Chain Rule to change the variable: \frac{dv}{dt}=\frac{dv}{dx}\frac{dx }{dt}=v\frac{dv}{dx} dt dv = dx dv dt dx =v dx dv .)

Explanation:

Given:

Now the kinetic frictional force:

where:

N= normal force of reaction by the ground on the car, which is equal to the weight of the car

Therefore the acceleration of the car due to frictional force:

Now the stopping distance:

number of electrons for neutral cl

gpe = mass x gravity constant x height or… gpe = mgh

where… mass: measured in kilograms (kg)

gravity: gravity constant on earth = 10.00 m/s2

height: measured in meters (m)

gpe: measured in joules (j) or kilojoules (kj)

how do you solve gpe?

gravitational potential energy (gpe) is the energy an object has because of its position above the. ground.

gpe = mass x gravity constant x height or… gpe = mgh.

mass:

note: to earn full marks when solving science word problems, you must show your work:

formula.

example:

given values:

mass = 0.3 kg.