A rod 8 cm long is uniformly charged and has a total charge of −21.8 μC. The Coulomb constant is 8.98755×10 N·m /C . Determine the magnitude of the electricfield along the axis of the rod at a point 42.279 cm from the center of the rod. Answer in units of N/C.

The magnitude of the electric field along the axis of the rod is 1.106 X 10⁶ N/C

Explanation:

The magnitude of the electric field along the axis of a rod is given as;

where;

λ is linear charge density, C/m

a is the distance from center of the rod, = (0.42279 - 0.08/2)m = 0.38279 m

L is the length of the rod,  = 0.08 m

ε is the permittivity of free space = 8.85 x 10⁻¹² C²/Nm²

λ  = Q/L = (21.8 μC)/0.08 = (21.8 * 10⁻⁶C)/0.08 = 2.725 x 10⁻⁴ C/m

1/4πε = k = 8.98755 x 10⁹ Nm²/C²

Solving for E

Therefore, the magnitude of the electric field along the axis of the rod is 1.106 X 10⁶ N/C

answer would be d.) i hope this

explanation:

answer: d. a cme increases the amount of energy in the solar wind

explanation:

coronal mass ejections, also called cmes, are large clouds of plasma and magnetic field that erupt from the sun. only when the cloud is aimed at earth will the cme hit earth and therefore cause impacts. high-speed solar wind streams come from areas on the sun known as coronal holes.