At 47 °C, what is the fraction of collisions with energy equal or greater than an activation energy of 88.20 kJ/mol?

The fraction of collision is

Explanation:

Given that,

Temperature = 47°C

Activation energy = 88.20 KJ/mol

From Arrhenius equation,

Here, =fraction of collision

We need to calculate the fraction of collisions

Using formula of fraction of collisions

Where f = fraction of collision

E = activation energy

R = gas constant

T = temperature

Put the value into the formula

Hence, The fraction of collision is

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