Saturated steam coming off the turbine of a steam power plant at 40oC condenses on the outside of a 7.421-cm-outer-diameter, 2.916-m-long tube at a rate of 16.154 kg/h. Calculate the rate of heat transfer in kW (give your answer with 3 decimals, do NOT enter units!!!).

Rate of heat transfer will be 10.69 kw

Explanation:

We have given temperature

From standard table enthalpy of vaporization 2382.75 KJ/kg

Steam is coming out from turbine at rate of 16.154 kg/hour

We have to calculate the rate of heat transfer

Heat transfer is equal to

So rate of heat transfer

=

So rate of heat transfer will be 10.69 kw

answer: 802.3 kilo joules of energy represents 191.75 kilo calorie of energy.

explanation:

energy released during combustion of one mole methane = 802.3 kilo joules

if 1 kilo joule = 0.239006   kilo calorie

then ,802.3 kilo joule will be = 802.30.239006 kilo calorie

802.3 kilo joule = 191.75 kilo calorie

hence, the energy in kilo calorie is 191.75 kilo calorie.