Suppose that the voltage of the battery in the circuit is 3.3 V, the magnitude of the magnetic field (directed perpendicularly into the plane of the screen) is 0.66 T, and the length of the rod between the rails is 0.19 m. Assuming that the rails are very long and have negligible resistance, find the maximum speed attained by the rod after the switch is closed.

Maximum velocity of rod will be equal to 26.315 m/sec

Explanation:

We have given voltage of the battery in the circuit V = 3.3 volt

Magnetic field B = 0.66 Tesla

Length of the rod l = 0.19 m

We know that emf is given by e = BVl

We have to find the maximum velocity of the rod

Here velocity is maximum

So

So

So maximum velocity of rod will be equal to 26.315 m/sec

12000j is work done