A projectile is launched at an angle of 19.0° above the horizontal. What is its initial speed if it hits a target that is located a horizontal distance of 175 m from the launch point and elevated 11.0 m from the launch level?

The initial speed of the projectile is 52.78 m/s

Explanation:

Applying equations of motion

The horizontal distance traveled by the projectile = R

R = u²sin2θ/g

where;

u is the initial speed of the projectile

g is acceleration due to gravity = 9.8

θ is the angle of projection = 19.0°

and given R = 175m

175 = u²sin2θ/g

175 = u²sin(2*19)/9.8

u²sin38⁰ = 1715

u² * 0.61566 = 1715

u²  = 1715/0.61566

u²  = 2785.628

u   = √2785.628

u   = 52.78 m/s

The initial speed of the projectile is 52.78 m/s

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thermal energy is the answer