What is the volume, in milimiters, of a 0.350 M KOH needed to completely neutralize 15.0 ml of a 0.250 M H2SO4 solution?

The volume of KOH needed for complete neutralization is 2.143 ml

Explanation:

Complete neutralization reaction is given below as;

H₂SO₄  + 2KOH ---------> K₂SO₄ + 2H₂O

Acid to base ratio, na : nb = 1 : 2

where;

is the concentration of the acid ( H₂SO₄) = 0.25 M

is the concentration of the base (KOH) = 0.35 M

is the volume of the acid = 15 ml

is the volume of the base = ?

The volume of KOH needed for complete neutralization is 2.143 ml

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