The voltage across a membrane forming a cell wall is 80.0 mV and the membrane is 10.00 nm thick. What is the electric field strength? You may assume a uniform electric field.

E= 8*10^5 V/m

Explanation:

solution:

electric field strength=v/d

given:

V=80 mV

d= 10 nm=10*10^-9 m

E=80 mV/10*10^-9 m

E= 8*10^5 V/m

8.00 x 10⁶ V/m

The voltage(V) across the membrane is related to the electric field strength (E) and the thickness (d) of the membrane as follows;

V = E x d          (i)

Where, according to the question;

V = 80.0mV = 80.0 x 10⁻³V

d = 10.00nm = 10.00 x 10⁻⁹m

Substitute these values into equation(i) to give;

80.0 x 10⁻³ = E x 10.00 x 10⁻⁹

Solve for E;

E = 80.00 x 10⁻³ / 10.00 x 10⁻⁹

E = 8.00 x 10⁶ V/m

Therefore, the electric field strength is 8.00 x 10⁶ V/m

answer: the exterior temperature of commercial jet planes as they leave the stratosphere and return to the ground increases steadily.

explanation:

the lower most layer of atmosphere is troposphere which extends from 0 to 12 km above the surface of the earth. the temperature initially decreases as distance is increased from the earth's surface. commercial jets fly in lower part of the stratosphere. the stratosphere extends upto 50 km. the temperature in stratosphere starts rising again due to presence of ozone which traps the uv rays.

thus, when the planes leave the stratosphere and return to the ground, the exterior temperature increases steadily.

i think they are all correct

explanation:

they seem good