Basidiomycete fungi ballistically eject millions of spores into the air by releasing the surface tension energy of a water droplet condensing on the spore. The spores are ejected with typical speeds of 1.09 m/s, allowing them to clear the "boundary layer" of still air near the ground to be carried away and dispersed by winds.
(a) If a given spore is accelerated from rest to 1.09 m/s in 7.85 µs, what is the magnitude of the constant acceleration of the spore (in m/s^2) while being ejected?

1.4 x 10^5 m/s^2.

Explanation:

Given the following:

vi = 0 m/s.

vf = 1.09 m/s.

t = 7.85 µs.

Using,

vf = vi + a*t

1.09 = a*7.8 x 10^-6

a = 139743.6

= 1.4 x 10^5 m/s^2.

mass and volume are the answers you are looking for

gpe = mass x gravity constant x height or… gpe = mgh

where… mass: measured in kilograms (kg)

gravity: gravity constant on earth = 10.00 m/s2

height: measured in meters (m)

gpe: measured in joules (j) or kilojoules (kj)

how do you solve gpe?

gravitational potential energy (gpe) is the energy an object has because of its position above the. ground.

gpe = mass x gravity constant x height or… gpe = mgh.

mass:

note: to earn full marks when solving science word problems, you must show your work:

formula.

example:

given values:

mass = 0.3 kg.