A baseball player hit 60 home runs in a season. Of the 60 home runs, 19 went to right field, 18 went to right center field, 12 went to center field, 10 went to left center field, and 1 went left field.
(a) What is the probability that a randomly selected home run was hit to leftleft field?
(b) Was it unusual for this player to hit a home run to leftleft field?

(a) 1/60

(b) Yes, it was unusual.

Explanation:

Number that went to the right field = 19

Number that went to the right center field = 18

Number that went to the center field = 12

Number that went to the left center field = 10

Number that went to the left field = 1

Total number of home runs = 60

(a) The probability that a randomly selected home run was hit to left field is

P(left field) = 1/60

(b) It was unusual because whenever a player hit a home run, it most times went to the right field,which is why the right field had the highest probability, 19/60.

On the other hand, it went to the left field the least number of times, which is why the left field had the least probability, 1/60.

So, it was unusual.

f=ma a/f/m a= 480/60 a = 8m/s/s that is quick wow