A space craft is traveling in interplanetary space at a constant velocity. what is the estimated distance traveled by the space craft in 9.50 seconds?
A. 2.30 x 10^2 kil
B. 2.42 x 10^2 kil
C. 2.51 x 10^2 kil
D. 3.02 x 10^2 kil

A. 2.30 x 10^2 kil

Explanation:

3/2 = 1.5 and 0.72/2 = 0.36

1.93 + 0.36 = 2.29

2.29 = about 2.30

anchor = archer //

the minimum constant speed at which she can catch the train is 2.7 m/s

given:

acceleration = 0.6

time = 4.5 s

to find:

velocity = ?

formula used:

from 1st kinematic equation we get,

v = u + at

u = initial speed of train = 0 m/s

v = final speed of the train

a = acceleration of the train

t = time

solution:

from 1st kinematic equation we get,

v = u + at

u = initial speed of train = 0 m/s

v = final speed of the train

a = acceleration of the train

t = time

v = 0 + (0.6 × 4.5)

v = 2.7 m/s

the minimum constant speed at which she can catch the train is 2.7 m/s