Two soccer players, Mia and Alice, are running as Alice passes the ball to Mia. Mia is running due north with a speed of 5.30 m/s. The velocity of the ball relative to Mia is 3.60 m/s in a direction 30.0 degree east of south.

A)What is the magnitude of the velocity of the ball relative to the ground?

B) What is the direction of the velocity of the ball relative to the ground?
Answer in north of east please

A. 2.83 m/s

B. 39.55 degrees north of east

Explanation:

The velocity of the ball relative to the ground is the sum vectors of velocity of the ball relative to Mia and the velocity of Mia relative to the ground

If we take north east as positive direction then

Velocity vector of the ball relative to Mia is

Velocity of Mia relative to gorund is

<0, 5.3>

So velocity of the ball relative to the ground is

<1.8, -3.12> + <0, 5.3> = <1.8, 2.18>

Its magnitude is:

 m/s

Its direction is

 north of east

weight of the box is given as

here this is placed on the inclined of angle 42 degree

now this weight will have two components one is along the incline other is perpendicular to it

so here we need to apply a force parallel to incline opposite to its component of weight

so here the component of weight is given as

here we have

so it requires 75 n force to move it upwards

the answer to this is proletariats.

hope this : )