When a large star becomes a supernova, its core may be compressed so tightly that it becomes a neutron star, with a radius of about 20 km (about the size of the San Francisco area). If a neutron star rotates once every second, what is the speed of a particle on the star's equator?

Speed,

Explanation:

Given that,

Radius of the neutron stare, R = 20 km = 20,000 m

Time taken by the Neutron star to rotate, t = 1 s

We need to find the speed of a particle on the star's equator. The total distance covered divided by total time taken is called speed of an object. Here,

v = 125663.70 m/s

or

So, the speed of a particle on the star's equator is . Hence, this is the required solution.

energy can be converted from one form to another, but it cannot be created or destroyed in ordinary chemical or physical means. do not understand what you are asking but hope this