Location A is 2.70 m to the right of a point charge q. Location B lies on the same line and is 3.80 m to the right of the charge. The potential difference VB - VA = 44.0 V. What is the magnitude and sign of the charge?

Point charge will be equal to

Explanation:

We have given distance of A from point charge

Distance of point B from point charge

We know that potential difference due to point charge is given as

So potential difference at point A

And potential difference at point B

We have given

So

So point charge will be equal to

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