What magnitude of charge would have to be transferred between a carpet and a shoe for there to be a 5.8 kV potential difference between the shoe and the carpet, approximating the shoe and the carpet as large sheets of charge separated by a distance d = 1.1 mm ? Approximate the area of a shoe as 30 cm x 8 cm.

1.12μC

Explanation:

From the expression use to determine the capacitance of a capacitor, which is given below

from the above since the distance,"d" is given is 1.1mm(0.0011m)

Area= 0.3m*0.08=0.024m

V=5.8KV

if we compare both equations above, we can  do away with the capacitance

if we substitute the value of the voltage, area, distance and the constant we arrive at

Hence the magnitude of the charge is 1.12μC

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