A bead slides down a vertical, helical track of radius 6.5 cm and height 32.9 cm with a constant speed of 2.4 cm/s. The helix is wound clockwise with 4 turns per cm down the axis. Take the origin to be at the bottom of the helix in the center of the spiral and the initial position of the bead to be in the x-z plane.

(a) What is the initial position of the bead? F(0) =6.5 cm V 32.9 cm 0 cm
(b) What is the position of the bead after the bead has fallen half the way to the bottom? 16.45 cm
(c) What is the vertical component of the bead's velocity? [Remember that it's falling.]
(d) How log did it take for the bead to travel half way down the helix?
(e) What is the velocity of the bead after it has fallen half the distance to the ground? dr/dt =
(f) What is the acceleration of the bead after it has fallen half the distance to the ground? d2F/dt2=
(g) What is the magnitude of the acceleration of the bead?