You charge a 2.00-μF capacitor to 50.0 V. How much additional energy must you add to charge it to 100 V?

The additional energy required to be added to charge the 2μF from 50V to a 100V is 0.0075J.

Explanation:

Energy of a capacitor is given by

E = CV²/2 where C is capacitance = 2μF = 2 × 10⁻⁶ F

When the capacitor is charged to 50V, the energy it has is,

E = (2 × 10⁻⁶ × 50²)/2 = 0.0025 J

When the capacitor is charged to 100V, the energy it has stored,

E = (2 × 10⁻⁶ × 100²)/2 = 0.01 J

Energy difference between being charged to 50V and being charged to 100V is,

0.01 - 0.0025 = 0.0075 J

This represents the additional energy required to be added to charge the 2μF from 50V to a 100V.

Hope this Helps!!!

answer: the metamorphic rocks are formed when they are exposed to high pressure and high temperatures. this happens when one of the earth's plates comes in contact with the other plate by traveling in opposite directions, straight into each other or slipping under one another. the friction that is caused by this activity results in   melting of rocks and when it cools they are known as metamorphic rocks. this process needs a controlled amount of pressure and temperature otherwise it may turn into magma.

high-sugar diet and high cholesterol