(a) What is the energy stored in the 10.0 μF capacitor of a heart defibrillator charged to 9.00×103V ? (b) Find the amount of stored charge.

(a)

(b)

Explanation:

(a) The potential energy stored in a capacitor is given by the expression:

Q is the stored charge and V the potential difference between capacitor plates. In a capacitor, we have:

Replacing this in the energy equation:

(b) Using the energy expression and solving for Q:

the total distance traveled by the car is

30km + 49km = 79 km .

initial speed when it is dropped is 150 ft/s

now at the same moment the acceleration due to gravity is perpendicular to its velocity

so as we know that

now we have centripetal acceleration a = 32 ft/s^2 as its perpendicular to velocity

while tangential acceleration at the same moment will be zero

so

now radius of curvature is given as

so the radius of curvature just after it is dropped is 703.125 ft