A speed boat moving at a velocity of 25 m/s runs out of gas and drifts to a stop 3 minutes later 100 meters away. What is its rate of deceleration?

The rate of deceleration is -0.14

Using one of the equations of motion;

v = u + at

where;

v = final velocity of the boat = 0m/s (since the boat decelerates to a stop)

u = initial velocity of the boat = 25m/s

a = acceleration of the boat

t = time taken for the boat to accelerate/decelerate from u to v =   3 minutes

Convert the time t = 3 minutes to seconds;

=> 3 minutes = 3 x 60 seconds = 180seconds.

Substitute the values of v, u, t into the equation above. We have;

v =  u + at

=> 0 = 25 + a(180)

=> 0 = 25 + 180a

Make a the subject of the formula;

=> 180a = 0 - 25

=> 180a = -25

=> a = -25/180

=> a = -0.14

The negative value of a shows that the boat is decelerating.

Therefore, the rate of deceleration of the speed boat is 0.14

i need the answer to this too but idk it ; -;

when two balls of the different masses are dropped from equal height, they reach the ground at the same time .this is because they experience the same acceleration.

the acceleration is independent of mass.

thus when they are dropped they will always maintain the same velocity and travel the same distance (neglect air resistance of course) at the same time.