Abowling ball is rolling in a straight line toward the pins at a speed of 2.2 m/s. its momentum is 4.75 kg*m/s. what is the
mass of the bowling ball?

m= 2.16 kg

Explanation: Momentum is expressed in the following formula:

p = mv

Derive to find m:

m = p / v

= 4.75 kg.m/s / 2.2 m/s

= 2.16 kg

Cancel out m/s and the remaining unit is in kg.

2.16kg

Explanation:

Mass=momentum/velocity

Mass=4.75/2.2

Mass=2.16kg

= initial pressure

= final pressure = 2

= initial volume

= final volume = /4

= initial temperature = 20 c = 20 + 273 = 293 k

= final temperature = ?

using the equation