If the specimen is loaded until it is stressed to 65 ksi, determine the approximate amount of elastic recovery after it is unloaded. express your answer as a length. express your answer to three significant figures and include the appropriate units.

ER = 0.008273 in

Explanation:

Given:

- Length of the specimen L = 2 in

- The diameter of specimen D = 0.5 in

- Specimen is loaded until it is stressed = 65 ksi

Find:

- Determine the approximate amount of elastic recovery after it is unloaded.

Solution:

- From diagram we can see the linear part of the curve we can determine the Elastic Modulus E as follows:

                                  E = stress / strain

                                  E = 44 / 0.0028

                                  E = 15714.28 ksi

- Compute the Elastic strain for the loading condition:

                                  strain = loaded stress / E

                                  strain = 65 / 15714.28

                                  strain = 0.0041364

- Compute elastic recovery:

                                   ER = strain*L

                                   ER = 0.0041364*2

                                   ER = 0.008273 in

1 a

2 b

3 b

4 d

5 d

6 d

explanation:

d₁ = displacement of tern from arctic to antarctic = 11000 miles

d₂ = displacement of tern from antarctic to arctic =   - 11000 miles

d = total displacement for the journey

total displacement for the journey is given as

d = d₁ + d₂

d = 11000 + (-11000)

d = 0 miles

t₁ = time of travel from arctic to antarctic = 3 months = 3 x 30 days = 90 days

t₂ = time of travel from antarctic to arctic = 3 months = 3 x 30 days = 90 days

t = total time of travel

total time of travel is given as

t = t₁ + t₂

t = 90 + 90

t = 180 days

average velocity is given as

average velocity = total displacement/ total time

v = d/t

v = 0/180

v = 0 miles/day