You have a remote-controlled car that has been programmed to have velocity v⃗ =(−3ti^+2t2j^)m/s, where t is in s. at t = 0 s, the car is at r⃗ 0=(3.0i^+2.0j^)mwhat is the x component of the car's position vector at 10 s? what is the y component of the car's position vector at 10 s? what is the x component of the car's acceleration vector at 10 s? what is the y component of the car's acceleration vector at 10 s?

The y-component of the car's position vector is 670m/s.

The x-component of the acceleration vector is -3, and the y-component is 40.

Explanation:

The displacement vector of the car with velocity

is the integral of the velocity.

Integrating we get the displacement vector :

Now if the initial position if the car is

then the displacement of the car at time is

Now at , we have

The y-component of the car's position vector is 670m/s.

The acceleration vector is the derivative of the velocity vector:

and at it is

The x-component of the acceleration vector is -3, and the y-component is 40.

answer: 2×10^-2kg

explanation: density= mass per volume

vol=mass/density

converting to s.i units we have;

3÷1000kg = 0.003

1.5÷100m = 0.15

0.003/0.15 = 0.02kg