You are driving to the grocery store at 20 m/s. you are 105 m from an intersection when the traffic light turns red. assume that your reaction time is 0.50 s and that your car brakes with constant acceleration.
(a) how far are you from the intersection when you begin to apply the brakes?
1 m
(b) what acceleration will bring you to rest right at the intersection?
2 m/s2
(c) how long does it take you to stop?

(a) 95m

(b) -2.11m/s^2

(c) 9.5s

Explanation:

(a). out of remaining 105m, for initial 0.5s I travel with constant speed:

  distace covered = 0.5s * 20m/s = 10m

   it means that I am 105-10 = 95m away from the intersection

(b) we apply the second equation of motion

     v^2 - u^2 = 2*a*s

so s = 95 m

     u = initial velocity = 20 m/s

     v = final velocity = 0 m/s ( comes to rest)

     0^2 - 20^2 = 2*a*95

        solving for 'a'

       a = -2.11 m/s^2    

(c)

     v-u = at

      0 - 20 = -2.11*t

solving for time t

 t = 9.5s

that would be because of both gravity and friction. so     c

a=d/t

a="triangle"v/t

explanation:

a = acceleration