If a 0.50-kg block initially at rest on a frictionless, horizontal surface is acted upon by a force of 3.7 n for a distance of 6.8 m, then what would be the block's velocity? m/s

The block's velocity is determined as 10.03 m/s.

Explanation:

According to work energy theorem, the work done on an object is equal to the change in kinetic energy of the object.

So, work done = Kinetic energy

Thus, the velocity can be determined as

Velocity = 10.03 m/s.

So the block's velocity is determined as 10.03 m/s.

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c. magnitude and direction