A7.0-μc point charge and a point charge are initially extremely far apart. how much work does it take to bring the point charge to the point , and the point charge to the point ( k = 1/4 πε 0 = 9.0 × 10 9 n ∙ m 2/c 2)?

Complete question:

A 7.0 -μC point charge and a 9.0 -μC point charge are initially infinitely far apart. How much work does it take to bring the 7.0-μC point charge to x=3.0 mm, y= 0.0mm and the 9.0-μC point charge to x=-3.0 mm, y=0.0 mm? (the value of k is 9.0*10^9 N*m^2/C^2)

Explanation:

Work done in bringing a unit positive charge from infinity to that point in electric filed (V) = Electric field strength X distance

where;

K is a constant = 9X10⁹ N.m²/C²

q is point charge in C

d is the distance in m

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Work done in bringing 7.0-μC point charge from infinity to x=3.0 mm, y= 0.0mm

V = 21 x 10⁶ Volts

Work done in bringing 9.0-μC point charge from infinity to x=-3.0 mm, y=0.0 mm

V = -27 x 10⁶ Volts

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Work done in bringing 7.0-μC point charge from infinity to x=3.0 mm, y= 0.0mm is 21 x 10⁶ Volts While work done in bringing 9.0-μC point charge from infinity to x=-3.0 mm, y=0.0 mm is -27 x 10⁶ Volts.

the moon affects the earth gravitation ally, causing certain motions of that body and also producing tides in its ocean and atmosphere. the tidal wave in our atmosphere is, however, far too minute to be an effective cause in any known meteorological phenomenon.

explanation:

pe = weightxheight = 2000x1000=2,000,000joules