An atwood machine consists of two masses m1 and m2 (with m1 > m2) attached to the ends of a light string that passes over a light, frictionless pulley. when the masses are released, the mass m1 is easily shown to accelerate down with an acceleration a = g ((m1 − m2) / ( m1 + m2))
1. suppose that m1 and m2 are measured as m1 = 100 ± 1 gram and m2 = 50 ± 1 gram. derive a formula of the uncertainty in the expected acceleration in terms of the masses and their uncertainties, and then calculate for the given numbers.

  1.the balanced   chemical equation is as below

cu +   2 ag(no)₃ → cu(no₃)₂   +2 ag

2.the   much silver   produced   is   50.9 g

step 1: find the   moles of cu

moles =   mass÷   molar mass

  from periodic table the molar mass of cu = 63.5 g/mol

moles is therefore = 15.00 g÷ 63.5 g/mol = 0.236   moles

step 2: use the mole ratio to determine the   moles of ag

from equation above   cu: ag   is 1: 2

therefore the moles of ag   =0.236   moles   x 2/1 =0.472   moles

step 3: find the mass   of ag

mass = moles x molar mass

from periodic table   the molar mass of ag =107.87 g/mol

mass   = 0.472   moles x 107.87 g/mol = 50.9 g

3.   the   much   silver   collected worth is   1.797 oz

  convert   50.9 g   to oz

that is   1 gram = 0.0353 oz

          50.9 grams =?   oz

by cross multiplication

={(50.9 grams x 0.0353 oz) / 1   gram}   =1.797 oz

area of focus