Two particles, one with charge − 7.97 × 10 − 6 c and the other with charge 2.71 × 10 − 6 c , are 0.0359 m apart. what is the magnitude of the force that one particle exerts on the other?

150.83 N

Explanation:

From coulomb's law,

F = kqq'/r² Equation 1

Where F = force between the particles, q = charge on the first particle, q' = charge on the second particle, r = distance between the particles, k = proportionality constant.

Given: q = 7.97×10⁻⁶ C, q' = 2.71×10⁻⁶ C, r = 0.0359 m.

Constant: k = 9.0×10⁹ Nm²/C²

Substitute into equation 1

F =(9.0×10⁹)( 7.97×10⁻⁶)(2.71×10⁻⁶ )/0.0359²

F = 194.3883×10⁻³/0.0012888

F = 150828.91×10⁻³

F = 150.83 N.

Hence the magnitude of the force that one particle exert on the other = 150.83 N

answer: d. a cme increases the amount of energy in the solar wind

explanation:

coronal mass ejections, also called cmes, are large clouds of plasma and magnetic field that erupt from the sun. only when the cloud is aimed at earth will the cme hit earth and therefore cause impacts. high-speed solar wind streams come from areas on the sun known as coronal holes.

force is mass*acceleration.

we have a very small mass: 11.4*0.001 kg

if we want 0.035n of force, we need an acceleration:

0.035 = 11.4*0.001*a

a = 0.035/(11.4*0.001) m/s^2