A(n) 10.7 g bullet is shot into a(n) 4588 g wooden block standing on a frictionless surface. the block, with the bullet in it, acquires a speed of 1.74 m/s. calculate the speed of the bullet before striking the block. answer in units of m/s

v = 747.83 m/s

Explanation:

given,

mass of bullet, m = 10.7 g

                             = 0.0107 Kg

mass of the wooden plank, M = 4588 g = 4.588 Kg

speed of the block and the bullet together, V = 1.74 m/s

initial speed of the plank = 0 m/s

using conservation of momentum

m v + M u = ( M + m ) V

0.0107 x v + 0 = (4.588 + 0.0107) x 1.74

0.0107 v = 8

v = 747.83 m/s

now, speed of the bullet is equal to 747.83 m/s.

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