A1425 kg car located at < 266, 0, 0 > m has a momentum of < 46000, 0, 0 > kg·m/s. what is its location 11 s later? (express your answer in vector form.)

<621, 0 , 0>

Explanation:

given,

mass of the car ,m = 1425 Kg

location of car = < 266, 0, 0 > m

momentum of the car = < 46000, 0, 0 > kg.m/s

M v_x = 46000

1425 x v_x = 46000

  v_x = 32.28 m/s

  v_y = 0 m/s

  v_z = 0 m/s

Location of the car after 11 s

x = v_x t + 266

x = 32.28 x 11 + 266

x = 621 m

hence, the location of car after 11 s is equal to  <621, 0 , 0>

as we know our atmosphere or air have different levels. every level has other gasses, and every gas has another permeability. when the light comes from lower permeability to higher permeability, it changes its direction. so that means that when the light comes from the moon to the earth, it changes it's direction many more times. it basically means that the shape of the light part of the moon is changed on the earth.

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