Afootball wide receiver rushes 16 m straight down the playing field in 2.9 s (in the positive direction). he is then hit and pushed 2.5 m straight backwards in 1.65 s. he breaks the tackle and runs straight forward another 24 m in 5.2 s.

part (a) calculate the wide receiver's average velocity in the horizontal direction during the first interval, in meters per second.

part (b) calculate the wide receiver's average velocity in the horizontal direction during the second interval, in meters per second.

part (c) calculate the wide receiver's average velocity in the horizontal direction during the third interval, in meters per second.

part (d) calculate the wide receiver's average velocity in the horizontal direction for the entire motion, in meters per second

a) v1 = 5.52m/s

b) v2 = -1.52m/s

c) v3 = 4.62m/s

d) vt = 3.85m/s

Explanation:

The velocity of the football wide receiver is his displacement per unit time.

Velocity v = (displacement d)/time t

v = d/t 1

For each of the cases, equation 1 would be used to calculate the velocity.

a) v1 = d1/t1

d1= 16m

t1 = 2.9s

v1 = 16m/2.9s

v1 = 5.52m/s

b) v2 = d2/t2

d2 = -2.5m

t2 = 1.65s

v2 = -2.5/1.65

v2 = -1.52m/s

c) v3 = d3/t3

d3 = 24m

t3 = 5.2s

v3 = 24/5.2

v3 = 4.62m/s

d) vt = dt/tt

dt = 16m - 2.5m + 24m = 37.5m

tt = 2.9 + 1.65 + 5.2 = 9.75s

vt = 37.5/9.75

vt = 3.85m/s

32: from largest to smallest, this hierarchy includes eons, eras, periods, epochs, and ages.

33: answer is c

i really hope this answer you out! it makes my day people like you and giving back to the community that has me through school! if you could do me a favor, if this you and this is the very best answer and you understand that all of my answers are legit and top notch. mark as brainliest! and have a awesome day!