Ashift in one fringe in the michelson-morley experiment corresponds to a change in the round-trip travel time along one arm of the interferometer by one period of vibration of light (about 2.0 x 10-15 s) when the apparatus is rotated by 9〫0. what velocity through the ether would be deduced from a shift of one fringe? (take the length of the interferometer arm to be 11 m).hint: you may find the following expansions for this problem and problems you will see later inthe class.

Explanation:

When Michelson-Morley apparatus is turned through then position of two mirrors will be changed. The resultant path difference will be as follows.

Formula for change in fringe shift is as follows.

          n =

             v =

According to the given data change in fringe is n = 1. The data is Michelson and Morley experiment is as follows.

             l = 11 m

           c = m/s

Hence, putting the given values into the above formula as follows.

            v =

               =

               =

Thus, we can conclude that velocity deduced is .

i think if it were me i whould divide 300 dide 15

step-by-step explanation:

what is the speed of a softball that travels 20m in 2secs

speed = 20/2 = 10 m/s