Aball is kicked from a location 7, 0, −8 (on the ground) with initial velocity −11, 19, −5 m/s. the ball's speed is low enough that air resistance is negligible. (a) what is the velocity of the ball 0.4 seconds after being kicked? (use the momentum principle! ) v = incorrect: your answer is incorrect. m/s

Explanation:

given,

location of the ball ⟨7,0,−8⟩

initial velocity of the ball ⟨-11,19,−5⟩

time = 0.4 s

speed of the ball = ?

using Momentum Principle

change in momentum = Force x time

Net force acting in this case will be equal to force due to gravity because air resistance is negligible.

F_net = F_g = ⟨0 ,-9.8 m , 0⟩

now,

hence, the velocity of the ball 0.4 s after being kicked is equal to

come closer and become far apart and become steam/gas

i think it's 35 meters