A732 kg car stopped at an intersection is rear-ended by a 1720 kg truck moving with a speed of 15.5m/s. if the car was in neutral and its breaks were off, so the collisions are approximately elastic, find the final speed of both vehicles after the collisions.

The final velocity of the car is 6.22 m/s and the final velocity of the truck is 21.72 m/s.

The given parameters;

The final velocity of both vehicles is calculated by applying the principle of conservation of linear momentum;

Apply one-directional linear velocity equation;

substitute the value of v₁ into the above equation;

Thus, the final velocity of the car is 6.22 m/s and the final velocity of the truck is 21.72 m/s.

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Truck= 6.25 m/s

Car= 21.7 m/s

Explanation:

For elastic collision, the truck's final velocity is given by

The car's final velocity is given by

Where m and u denote masses and velocity respectively, subscripts 1 and 2 denote truck and car respectively.

Substituting 1720 Kg for mass of truck, 732 for mass of car and initial velocity as 15.5 m/s

Therefore, the final velocity of truck is 6.25 m/s while the car's final velocity is 21.7 m/s

the rearrangement of particles in a physical change. hope this