At the equator, the radius of the earth is approximately 6370 km. a plane flies at a very low altitude at a constant speed of v = 219 m/s. upon landing, the jet can produce an average deceleration of a=17 m/s^2. how long will it take the plane to circle the earth at the equator?

To solve this problem we will apply the concepts related to the kinematic equations of linear motion. For this purpose we will define the speed as the distance traveled in a given period of time. Here the distance is equivalent to the orbit traveled around the earth, that is, a circle. Approaching the height of the aircraft with the radius of the earth, we will have the following data,

The circumference of the earth would be

Velocity is defined as,

Here, then

Therefore will take s or 506 hours, 19 minutes, 17 seconds

acceleration = (change in speed) / (time for the change)

change in speed = (20-120)= -100 m/s.

1.5 min = 90 sec

acceleration = -100/90 = -1.11 m/s^2.

we don't care about the 150kg or the 2,500 meters. they don't make any difference.

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