Knowing the p is 1110 n, determine the tension in the rope if the frame is in equilibrium. express your answer in kn to the nearest 10 n.

Explanation:

It is given that the value of P is 1110 N. And, for pin connection we have only two connections which are and . Let T be the tension is rope.

So,   and - 1110 = 0

      = 0

And,     = 0

                  T =

Also, = 0

                1110(0.75 + 0.75 + 0.75) - T(0.5 + 0.1) = 0

                    2497.5 - 0.6T = 0

                         T = 4162.5 N

                             = 4.16 kN

Therefore, we can conclude that the tension in the rope if the frame is in equilibrium is 4.16 kN.

does it have any answear choices.

explanation:

reserve is the answer