If the torque required to loosen a nut that is holding a flat tire in place on a car has a magnitude of 50 n·m, what minimum force must be exerted by the mechanic at the end of a 22 cm-long wrench to loosen the nut? answer in units of n.

227.27 N

Explanation:

Torque: This can be defined as the force that tend to cause an object to twist or rotate. the torque of a body is also called moment of a body. The S.I unit of torque is N.m.

Mathematically

T = F×d Equation 1

Making F the subject of the equation,

F = T/d Equation 2

T = torque required to loosen the nut, F = force applied  , d = distance between the force and the center of the nut.

Given: T = 50 N.m, d = 22 cm = (22/100) = 0.22 m.

F = 50/0.22

F = 227.27 N.

Thus the minimum force required to loosen the nut = 227.27 N

the total distance traveled by the car is

30km + 49km = 79 km .