You pull your car into your driveway and stop. the drive shaft of your car engine, initially rotating at 2400 rpm, slows with a constant rotational acceleration of magnitude 30 rad/s2.

Complete question is: You pull your car into your driveway and stop. The drive shaft of your car engine, initially rotating at 2400 rpm,slows with a constant rotational acceleration of magnitude 30 rad/s². How long does it take for the drive shaft to stop turning?

8.37 s

Explanation:

Initial rotational velocity, ω₀ = 2400 rpm = 2400 × 2π/60 = 251.2 rad/s

Final velocity, ω = 0

rotational deceleration, α =- 30 rad/s²

Use the first equation of rotational motion:

Substitute the values:

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