While floating in space a 100.-kg robot throws a 0.800-kg wrench at 12.0 m/s toward its human partner working on the spaceship. how fast will the robot recoil?

   v = - 0.096 m/s

Explanation:

given,

mass of the robot, M = 100 Kg

mass of wrench, m = 0.8 Kg

speed of the wrench,v' = 12 m/s

recoil of the robot,v = ?

initial speed of the robot and the wrench is equal to zero

using conservation of motion

(M + m) V = M v + m v'

(M + m) x 0 = 100 x v + 0.8 x 12

100 v = -9.6

   v = - 0.096 m/s

negative sign shows that velocity of robot is in opposite direction of wrench.

hence, the recoil velocity of the robot is equal to 0.096 m/s

in simple terms, the principle states that the buoyancy force on an object is equal to the weight of the fluid displaced by the object, or the density of the fluid multiplied by the submerged volume times the gravitational acceleration, g. this is also known as upthrust.

the answer is f1 and d2 because if you put equal force on those two points the beam would balance trust me on this