Acargo elevator on earth (where g = 10 m/s2) lifts 3000 kg upwards by 20 m. 720 kj of electrical energy is used up in the process. what is the efficiency of this process?

83%

Explanation:

Efficiency of the process = work output/work input × 100%

Work input is the energy used up in the process = 720,000Joules

Work output = Force × distance

= (3000×10)× 20

= 600000 Joules

Efficiency= 600000/720000 × 100

= 0.83×100

= 83%

the inner core.

good luck: )

klicker

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