The force exerted on the small piston of a hydraulic lift is 780 n . if the area of the small piston is 0.0075 m2 and the area of the large piston is 0.13 m2, what is the force exerted by the large piston?

13520 N

Explanation:

Pascal's Principle: The principle states that the pressure applied to an enclosed fluid is transmitted undiminished to every portion of the fluid and the walls of the containing vessel.

The operation of hydraulic press and car brake system is based on pascal's principle.

From pascal's principle,

F/A = f/a Equation 1

Where F = force exerted by the large piston, A = area of the large piston, f = force applied to the small piston, area of the small piston.

Making F the subject of the equation

F = A(f/a) Equation 2

Given: A = 0.13 m², a = 0.0075 m², f = 780 N

Substituting into equation 2

F = 0.13(780/0.0075)

F = 13520 N.

Thus the force exerted by the large piston = 13520 N

real, smaller and upside-down.   so the answer should be b.