Aplatform is rotating with an angular speed of 3.00 rad/s and an angular acceleration of 11.0 rad/s2. at a point on the platform that is 1.40 m from the axis of rotation, what is the magnitude of the total acceleration a?

a=19.8977 m/s²

Explanation:

Given data

ω=3.00 rad/s

r=1.40 m

α=11.0 rad/s²

To find

Acceleration

Solution

As the object moves in a circle so it has tangential acceleration also due to circular motion  is  has centripetal acceleration

The total acceleration can be found by

where

at is tangential acceleration

ac is centripetal acceleration

First we need to find centripetal acceleration

so

put the values or r and ω

Now for tangential acceleration

Put values of ac and at to find total acceleration

So

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explanation:

explanation:

earth's surface is mainly heated by the absorption of infrared radiation from the sun.

evaporation occurs because molecules in liquid water are warmed ( usually by the sun) and vibrate quicker, becoming less dense and rise.

condensation occurs because molecules in water vapor are cooled and therefore vibrate more slowly thus becoming more dense and eventually fall to earth.

lines of equal barometric pressure on a weather map are called: isobars : lines of equal temp on a weather map are called: isotherms.​