Acharge q is transferred from an initially uncharged plastic ball to an identical ball 17 cm away. the force of attraction is then 68nm .
how many electrons were transferred from one ball to the other?

2.92 x 10¹² electrons

Explanation:

given,

distance between two plastic ball, r = 17 cm

                                      r = 0.17 m

Force of attraction = F = 68 mN

                F = 0.068 N

number of electron transferred from one ball to another.

using Coulomb Force equation

q² = 2.1835 x 10⁻¹³

q = 4.67 x 10⁻⁷ C

now, number of electron

e is the charge of electron which is equal to 1.6 x 10⁻¹⁹ C

       N = 2.92 x 10¹² electrons

electrons were transferred from one ball to the other is 2.92 x 10¹²

Field strength is directly proportional to the square of charge. The charge on the given plastic ball is

Where,

- field strength = 68 mN = 0.06 N

- charge

- distance =  17 cm =0.17 m

- constant = 9x10⁹

Put the values in the formula,

Therefore, the charge on the given plastic ball is .

To know more about Coulomb  law:

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gpe = mass x gravity constant x height or… gpe = mgh

where… mass: measured in kilograms (kg)

gravity: gravity constant on earth = 10.00 m/s2

height: measured in meters (m)

gpe: measured in joules (j) or kilojoules (kj)

how do you solve gpe?

gravitational potential energy (gpe) is the energy an object has because of its position above the. ground.

gpe = mass x gravity constant x height or… gpe = mgh.

mass:

note: to earn full marks when solving science word problems, you must show your work:

formula.

example:

given values:

mass = 0.3 kg.