Physics, 23.01.2020 05:31 913003853

The amount of gravity between 1kg of lead and earth is the amount of gravity between 1kg of marshmallows and earth.

a. greater than
b. less than
c. the same as
d. none of the above

Answers: 2

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The attraction pull from the earth to the other heavy bodies is called gravitation. The gravitation depends on these factors:-

MassDistance

The heavier the mass, the more the gravitation pull works but the distance is inversely proportional to the gravity. Hence, the more the distance less the gravitation force.

The weight of an object is the force acting on the object due to gravity.

According to the question, the weight of the 1kg lead and the 1kg marshmallows is the same because both have equal weight.

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Answer from: queenkimm26

The amount of gravity between 1 kg of lead and Earth is the same as the amount of gravity between 1 kg of marshmallows and Earth.

Option C

Explanation:

According to universal law of gravity, the gravitational force is directly proportionate to the product of masses of the interacting objects and inversely proportionate to its distance squared between them.

Since the mass of Earth is very high compared to the mass of the other objects, be it lead or marshmallows, and the distance will be mostly same. Thus, there will be no change in the amount of gravity acting between them. Thus, the amount of gravity between 1 kg of lead and Earth is the same as the amount of gravity between 1 kg of marshmallows and Earth.

Answer from: Quest

causes

fossil fuels burn

cities become more industrialized

human population grows worldwide

Answer from: Quest

when jerome paddle in flowing river towards east the net speed of jerome will increase

so the net speed of jerome will be given as

$v_j = v_1 + v_2 = 3.100 + 1.350 = 4.45 m/s$

now the speed of paul will be same as it is given as he is running on the ground

$v_p = 3.100 m/s$

so here we can say since the speed of jerome is more so he will win the race

now as we know the distance so the time difference is given as

$\delta t = \frac{d}{v_j} - \frac{d}{v_p}$

$\delta t = \frac{2080}{4.450} - \frac{2080}{3.100}$

$\delta t = -203.55 s$

so jerome will reach first and the time difference will be 203.55 s or 3.4 min

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