Wo baseballs are fired into a pile of hay. if one has twice the speed of the other, how much farther does the faster baseball penetrate?

Explanation:

Given

Two baseballs are fired into a pile of hay such that one has twice the speed of the other.

suppose u is the velocity of first baseball

so velocity of second ball is 2u

suppose and are the penetration by first and second ball

using

where v=final velocity

u=initial velocity

a=acceleration

d=displacement

here v=0 because ball finally stops

for second ball

divide 1 and 2 we get

as deceleration provided by pile will be same

thus faster ball penetrates 4 times of first ball