If the gas in a container absorbs 275 joules of heat, has 125 joules of work done on it, then does 50 joules of work, what is the increase in the internal energy of the gas?

The internal energy of the gas is the energy contained by the gas. The increase in the internal energy of the gas in the given container is 350 J.

The internal energy of the gas can be calculated by the formula

Q= ΔU + W(net)

Where,

Q - energy absorbed by the system = 275  J

ΔU - internal energy of the gas= ?

W(net)=  W - W' = -125  + 50 = -75 J

Put the values in the formula,

275 = ΔU -75

ΔU= 275 + 75 J

ΔU=350 J

Therefore, the increase in the internal energy of the gas in the given container is 350 J.

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    The increase in the internal energy = 350 J

Explanation:

Given that

Q= 275  J

W= - 125 J

W' = 50 J

W(net)= -125  + 50 = -75 J

Sign -

1.Heat rejected by system - negative

2.Heat gain by system - Positive

3.Work done by system = Positive

4.Work done on the system-Negative

Lets take change in the  internal energy =ΔU

We know that

Q= ΔU + W(net)

275 = ΔU -75

ΔU= 275 + 75 J

ΔU=350 J

The increase in the internal energy = 350 J

3. dark matter

empty space could also be a simple vacuum